A function f is defined by f(x) = 2x - 5. Write down the values of:

(i) f(0) (ii) f(7) (iii) f(-3)

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Solution

Here f(x) = 2x - 5

(i) Putting x = 0

$∴ f (0) = 2 \times 0 - 5 = - 5$

(ii) Putting x = 7

$∴ f (7) = 2 \times 7 - 5 = 9$

(iii) Putting x = -3

$∴ f (- 3) = 2 \times - 3 - 5 = - 11$

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f (x) = 2 x - 5

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{\frac{- 3}{5}} \to R

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Let $f : R \to R$ be the function defined by $f (x) = 2 x - 3, \forall x \in R$ . Write $f^{- 1}$ .

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f (x) = 2 x + 3

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f (- \frac{2}{5}) =

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