A function f of the complex variable z=x+iy, is given as f(x,y)=u(x,y)+iv(x,y),whereu(x,y)=2kxy and v(x,y)=x2−y2. The value of k, for which the function is analytic, is
-1
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Solution
The correct option is A -1 u(x,y)=2kxy and v(x,y)=x2−y2
Now, ∂u∂x=∂v∂yand∂u∂y=−∂v∂x ⇒2ky=−2y and 2kx=−2x ⇒k=−1 and k=−1