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Question

A function f:RR is defined as f(x)=3x2+1. Then f1(x) is :

A
x13
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B
13x1
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C
14x1
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D
x+13
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Solution

The correct option is A x13
f(x)=3x2+1
Letf(x)=y
y=3x2+1
Putting xforyx=3y2+13y2=x1y2=x13y=sqrtx13f1(x)=x13

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