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Other
Engineering Mathematics
Limit Continuity and Differentiality
A function fx...
Question
A function f(x) is defined as
f
(
x
)
=
⎧
⎪
⎨
⎪
⎩
3
x
+
4
x
<
0
−
4
x
=
0
4
−
6
x
x
>
0
then at x = 0 for f(x)
A
Limit does not exists
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B
Limit exists but discontinous
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C
Limit exists and is continuous
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D
Is not defined
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Solution
The correct option is
B
Limit exists but discontinous
For limit to exist, LHL = RHL
Now,
RHL
l
i
m
x
→
0
+
f
(
x
)
=
4
−
6
x
=
4
LHL
l
i
m
x
→
0
−
f
(
x
)
=
3
x
+
4
=
4
⇒
Limit exists
Now for continuity,
LHL = RHL = Functional value
At x = 0
f
(
x
)
=
−
4
≠
R
H
L
⇒
Discontinous
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