A function f x is given by the equation - x2 f- x - 2 x f x - x - 1 - 0 - f 1 - 0- fx -ax2-bx-1px2-qx-r- then a2 - b2 - p2 - q2 - r2 -

The correct option is B 9 ddx[x^2 y]= x 1 where y = f (x) x^2 y= ∫ (x 1) d x This gives y =12 1x+12x^2 ...

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A function f ...

Question

A function f (x) is given by the equation , $x^{2} f^{'} (x) + 2 x f (x) - x + 1 = 0, f (1) = 0$ .
$f (x) = \frac{a x^{2} + b x + 1}{p x^{2} + q x + r}$ , then $a^{2} + b^{2} + p^{2} + q^{2} + r^{2}$ =

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Solution

The correct option is B 9
$\frac{d}{d x} [x^{2} y] = x - 1$ where $y = f (x)$

$x^{2} y = \int (x - 1) d x$

This gives $y = \frac{1}{2} - \frac{1}{x} + \frac{1}{2 x^{2}}$

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A function f (x) is given by the equation , x2f′(x)+2xf(x)−x+1=0,f(1)=0.f(x)=ax2+bx+1px2+qx+r, then a2+b2+p2+q2+r2 =

The correct option is B 9ddx[x2y]=x−1 where y=f(x)x2y=∫(x−1)dxThis gives y=12−1x+12x2

A function f (x) is given by the equation , $x^{2} f^{'} (x) + 2 x f (x) - x + 1 = 0, f (1) = 0$ .
$f (x) = \frac{a x^{2} + b x + 1}{p x^{2} + q x + r}$ , then $a^{2} + b^{2} + p^{2} + q^{2} + r^{2}$ =

The correct option is B 9
$\frac{d}{d x} [x^{2} y] = x - 1$ where $y = f (x)$

$x^{2} y = \int (x - 1) d x$

This gives $y = \frac{1}{2} - \frac{1}{x} + \frac{1}{2 x^{2}}$