Question

A function f(x) is such that it is not differentiable at two points h, k in its domain and f’(x) becomes zero at 3 points a, b, c in the domain. The critical points and stationary points will be -

• A. 3, 3
• B. 5, 5
• C. 5, 3
• D. 3, 5

Answer 1

The correct option is C

5, 3

Stationary points are the points in the domain of f(x) where f’(x) = 0. We are given f’(x) is zero at three points in the domain. So the number of stationary points will be 3.

Critical points are the points where f'(x) is zero or it doesn't exist. f’(x) is not defined at two points and f’(x) becomes zero three times in the domain. So, there will be 5 critical points.

Number of critical points is 5 and number of stationary points is 3