A function is given as y-5 x2-10 x- thenA- Minimum value of y is -5B- Maximum value of y is 10C- Maximum value of y is 0D- Maximum value of y occurs at x -1

The correct option is A Minimum value of y is 5By maxima or minima ⇒dy/dx = 0 ⇒ 10x 10 = 0 ⇒ x = 1 At x = 1, d^2y/dx^2 = 10 which is positive. ∴ At x= 1, ...

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Standard XII

Physics

Differentiation

A function is...

Question

A function is given as $y = 5 x^{2} - 10 x$ , then

Maximum value of y is 10

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Minimum value of y is -5

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Maximum value of y is 0

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Maximum value of y occurs at x = 1

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Solution

The correct option is B Minimum value of y is -5
By maxima or minima $\Rightarrow \frac{d y}{d x} = 0$
$\Rightarrow 10 x - 10 = 0 \Rightarrow x = 1$
At $x = 1, \frac{d^{2} y}{d x^{2}} = 10$ which is positive.
$∴ A t x = 1,$ there is a minima.
$y_{m i n} = y (1) = 5 - 10 = - 5$ .

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A function is given as y=5x2−10x, then

The correct option is B Minimum value of y is -5By maxima or minima ⇒dydx=0 ⇒10x−10=0⇒x=1 At x=1,d2ydx2=10 which is positive. ∴ At x=1, there is a minima. ymin=y(1)=5−10=−5.

A function is given as $y = 5 x^{2} - 10 x$ , then

The correct option is B Minimum value of y is -5
By maxima or minima $\Rightarrow \frac{d y}{d x} = 0$
$\Rightarrow 10 x - 10 = 0 \Rightarrow x = 1$
At $x = 1, \frac{d^{2} y}{d x^{2}} = 10$ which is positive.
$∴ A t x = 1,$ there is a minima.
$y_{m i n} = y (1) = 5 - 10 = - 5$ .