A function: R ⟶ R satisfies the equation f(x) f(y) -f(xy) = x+ y ∀ x, y ∈ R and f(1) > 0, then
f(x) f-1 (x)=x2 - 4
f(x) f-1 (x)=x2 - 6
f(x) f-1 (x)=x2 - 1
f(x) f-1 (x)=x2 + 6
∴ f(x). f-1 (x)=x2 - 1
Factorise: x4-1