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Question

A function: R R satisfies the equation f(x) f(y) -f(xy) = x+ y x, y R and f(1) > 0, then


A

f(x) f-1 (x)=x2 - 4

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B

f(x) f-1 (x)=x2 - 6

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C

f(x) f-1 (x)=x2 - 1

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D

f(x) f-1 (x)=x2 + 6

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Solution

The correct option is C

f(x) f-1 (x)=x2 - 1


Taking x = y =1, we get
f(1)f(1)-f(1)=2
f2 (1) - f(1) - 2 = 0 (f(1)-2) (f(1)+1)=0
f(1) = 2 (as f(1)>0)
Taking y =1. we get
f(x). f(1)-f(x) = x+1
f(x) = x + 1 f-1(x)=x - 1

f(x). f-1 (x)=x2 - 1


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