Question

$A\left(g\right)+3B\left(g\right)\rightleftharpoons 4C\left(g\right)$. Starting concentration of $A$ is equal to $B$, equilibrium concentration of $A$ and $C$ are same. $K_c:$

• A. $0.08$
• B. $0.8$
• C. $8$
• D. $80$

Answer 1

The correct option is C $8$

$A_{\left(g\right)}+3B_{\left(g\right)}\rightleftharpoons 4C_{\left(g\right)}$
$x$ $x$
$x-y$ $x-3y$ $4y$
$x-y=4y$
$x=5y$
$K_c=\frac{[C{]}^4}{\left[B{]}^3\right[A]}$
$=\frac{(4y{)}^4}{(x-3y{)}^3(x-y)}$
$=\frac{(4y{)}^4}{\left(2y{)}^3\right(4y)}$
$=\frac{4\times 4\times 4\times 4y^4}{8\times 4\times y^4}$
$=8$