$A$ g of sulphur and $B$ g of oxygen are allowed to react to form $S O_{2}$ . What will be the ratio of $A : B$ ?

1 : 1

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1 : 2

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1 : 3

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1 : 4

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Solution

The correct option is A $1 : 1$
$S (32 ℊ) + O_{2} ((16 \times 2) ℊ) ⟶ S O_{2}$
$\Rightarrow$ Ratio of A and B is $1 : 1$

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Q. 2 g

H_{2}

and 1 g

O_{2}

are allowed to react according to following equation:

2 H_{2} (g) + O_{2} (g) \to 2 H_{2} O (g)

Amount of

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formed in the reaction will be:

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$H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O$

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(a) $0.1 m o l L^{- 1}$ (b) $7.10 g$

In what ratio does sulphur and oxygen need to be added in order to increase the yield of SO₂ in the contact process?

Hydrogen and oxygen combine in a ratio of 1:8 by mass to form water. What mass of oxygen gas is required to react completely with 3g of hydrogen gas?

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A g of sulphur and B g of oxygen are allowed to react to form SO2. What will be the ratio of A:B ?

The correct option is A 1:1S(32ℊ)+O2((16×2)ℊ)⟶SO2⇒Ratio of A and B is 1:1

$A$ g of sulphur and $B$ g of oxygen are allowed to react to form $S O_{2}$ . What will be the ratio of $A : B$ ?

The correct option is A $1 : 1$
$S (32 ℊ) + O_{2} ((16 \times 2) ℊ) ⟶ S O_{2}$
$\Rightarrow$ Ratio of A and B is $1 : 1$