$A (g) \to B (g) + C (g)$

$\frac{- d [A]}{d t} = k [A]$

At the start, the pressure is 100 mm and after 10 min, the pressure is 120 mm. Hence, rate constant $(m i n^{- 1})$ is:

\frac{2.303}{10} l o g (\frac{120}{100})

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\frac{2.303}{10} l o g (\frac{100}{20})

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\frac{2.303}{10} l o g (\frac{100}{80})

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\frac{2.303}{10} l o g (\frac{100}{120})

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Solution

The correct option is C $\frac{2.303}{10} l o g (\frac{100}{80})$
$A (g) \to B (g) + C (g)$

$t = 0$ P 0 0
At time t P-x x x

Total pressure $= P - x + x + x = 120$ .
$P + x = 120$

$x = 120 - P = 120 - 100 = 20.$

$k = \frac{2.303}{t} l o g \frac{a}{a - x}$

$k = \frac{2.303}{10} l o g \frac{100}{80}$

Hence, option C is correct.

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Similar questions

$A (g) \to B (g) + C (g)$

- $\frac{d [A]}{d t} = k [A]$

At the beginning of this reaction, the pressure is 100 mm Hg. After 10 min, pressure increases to 120 mm Hg. The rate constant $(m i n^{- 1})$ is:

Q. A gaseous reaction

A_{2} (g) ⇌ B (g) + 1 / 2 C (g)

shows increase in the pressure from 100 mm to 120 mm in 5 min. The rate of disappearance of

A_{2}

is:

Q. A gaseous reaction :

A_{2} (g) ⇌ B (g) + \frac{1}{2} C (g)

shows increase in the pressure from 100 mm to 120 mm in 5 min. The rate of disappearance of

A_{2}

is:

Half - life of the reaction : $H_{2} O_{2 (a q)} \to H_{2} O_{ℓ} + \frac{1}{2} O_{2 (g)}$ is independent of initial concentration of $H_{2} O_{2}$ . Volume of $O_{2}$ gas after 20 minutes is 5L at 1 atm and $27^{\circ} C$ , and after completion of the reaction 50 L. The rate constant is :

Q. Rate constant

k = 2.303 m i n^{- 1}

for a particular reaction.The initial concentration of the reaction is

1 m o l / l i t r e

then, rate reaction after

1

minute is:

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A(g)→B(g)+C(g)−d[A]dt=k[A] At the start, the pressure is 100 mm and after 10 min, the pressure is 120 mm. Hence, rate constant (min−1) is:

The correct option is C 2.30310log(10080) A(g)→B(g)+C(g)t=0 P 0 0 At time t P-x x xTotal pressure =P−x+x+x=120.P+x=120x=120−P=120−100=20.k=2.303tlogaa−x k=2.30310log10080Hence, option C is correct.

$A (g) \to B (g) + C (g)$

$\frac{- d [A]}{d t} = k [A]$

At the start, the pressure is 100 mm and after 10 min, the pressure is 120 mm. Hence, rate constant $(m i n^{- 1})$ is: