A Galileo telescope has an objective of focal length $100$ cm & magnifying power $50$ . The distance between the two lenses in normal adjustment will be?

150

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100

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98

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200

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Solution

The correct option is B $98$ cm
$m = \frac{f_{0}}{f_{e}}$

$m$ is magnifying power of the objective lens
and $f_{e}$ is the focal length of the eye
$f_{0} = \frac{f_{e}}{m}$

$f_{0} = \frac{100}{50} = 2 c m$

length of galileo telescope

$l = f_{0} - f_{e}$

$l = 100 - 2 = 98$ cm

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A Galileo telescope has an objective of focal length 100 cm & magnifying power 50. The distance between the two lenses in normal adjustment will be?

The correct option is B 98 cmm=f0fem is magnifying power of the objective lens and fe is the focal length of the eyef0=femf0=10050=2cmlength of galileo telescopel=f0−fel=100−2=98 cm

A Galileo telescope has an objective of focal length $100$ cm & magnifying power $50$ . The distance between the two lenses in normal adjustment will be?

The correct option is B $98$ cm
$m = \frac{f_{0}}{f_{e}}$

$m$ is magnifying power of the objective lens
and $f_{e}$ is the focal length of the eye
$f_{0} = \frac{f_{e}}{m}$

$f_{0} = \frac{100}{50} = 2 c m$

length of galileo telescope

$l = f_{0} - f_{e}$

$l = 100 - 2 = 98$ cm