You visited us 1 times! Enjoying our articles? Unlock Full Access!

Electrode Potential

A galvanic ce...

Question

A galvanic cell consists of a metallic. zinc plate immersed in 0.1 M $Zn {(N O_{3})}_{2}$ solution and metallic plate of lead in 0.02 M $Pb {(N O_{3})}_{2}$ solution. Calculate the emf of the cell write the chemical equation for the electrode reactions and represent the cell. (Given $E_{Z n^{2 +}, Z n}^{\circ} = - 0.76 V, E_{P b^{2 +}, P b}^{\circ} = 0.13 V$ )

Open in App

Solution

At anode $Z n \to Z n^{2 +} + 2 e^{-}$
At cathode $P b^{2 +} + 2 e^{-} \to P b$

Cell representation
$Z n / Z n (N O_{3})_{2} (0.1 M) | | P b (N O_{3})_{2} (0.02 M) / P b$

$E = E^{o} - \frac{0.0591}{n} l o g \frac{Z n^{2 +}}{P b^{2 +}}$

$E = (0.76 + 0.13) - \frac{0.0591}{2} l o g \frac{0.1}{0.02}$

$E = 0.08693 v$

Suggest Corrections

Similar questions

0.1 M Z n (N O_{3})_{2}

25^{\circ} C

E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 v o l t

E_{P b^{2 +} / P b}^{\circ} = - 0.13 v o l t

E_{(P b^{2 +} | P b)}^{⊖} = - 0.126 V, E_{(Z n^{2 +} | Z n)}^{⊖} = - 0.763 V

25^{\circ} C

Z n | Z n^{2 +} (1 M) | | P b^{2 +}

P b^{2 +}

P b^{2 +}

2.5 \times 10^{- x} M

Z n (s) + 2 H^{+} (aq) \to Z n^{2 +} (0.1 M) + H_{2} (g, 1 bar)

0.28 V

25^{\circ} C

E_{Z n^{2 +} | Z n}^{\circ} = - 0.763 V

Z n + 2 H^{+} (a q .) \to Z n^{2 +} (0.1 M) + H_{2} (g) 1 a t m

0.28

25^{\circ} C

p H

E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 v o l t

E_{H^{+} / H_{2}}^{\circ} = 0

Z n^{2 +} + 2 e^{-} \to Z n; E = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E = - 0.44 V

F e^{2 +} = Z n^{-} \to Z n^{2 +} + F e

Join BYJU'S Learning Program