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Question

A galvanic cell consists of a metallic. zinc plate immersed in 0.1 M Zn(NO3)2 solution and metallic plate of lead in 0.02 M Pb(NO3)2 solution. Calculate the emf of the cell write the chemical equation for the electrode reactions and represent the cell. (Given EZn2+,Zn=0.76V,EPb2+,Pb=0.13V)

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Solution

At anode ZnZn2++2e
At cathode Pb2++2ePb

Cell representation
Zn/Zn(NO3)2(0.1M)||Pb(NO3)2(0.02M)/Pb

E=Eo0.0591nlogZn2+Pb2+

E=(0.76+0.13)0.05912log0.10.02

E=0.08693v


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