wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A galvanic cell is formed by immersing Ag(s) in AgNO3(aq,0.1 M) and Cu(s) in CuSO4(aq,4M) at 298 K
Calculate the EMF of the cell.
Given:
E0Ag+/Ag=0.80 V
E0Cu2+/Cu=0.34 V

A
Ecell= 0.301 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Ecell= 0.383 V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Ecell= 0.45 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Ecell= 1.04 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B Ecell= 0.383 V
Standard reduction potential of Ag+/Ag couple has value higher value, hence, it will act as cathode and Cu2+/Cu will act as anode.

Thus, the cell representation will be,
Cu(s)Cu2+(aq, 4.0 M)Ag+(aq, 0.1 M)Ag(s)
Cell reaction is
Cu+2Ag+Cu2++2Ag
Here n = 2;
E = E0cell 0.0592log[Cu2+][Ag+]2
E0cell=E0cathodeE0anode
E0cell=0.800.34
E0cell=0.46 V

By Nernst equation,
Ecell=0.46 0.0592log[4.0][0.1]2
Ecell= 0.46 0.0592 log (4 × 102)
Ecell= 0.46 0.0592×0.6020.059
Ecell= 0.46 0.0180.059
Ecell= 0.46 0.077
Ecell= 0.383 V

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon