A galvanometer has a coil of resistance 50 Ω and shows full deflection for 100 Ω A. The resistance to be added to the galvanometer to work as an ammeter of range 10 mA is
A
0.5 Ω in series
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B
0.5 Ω in parallel
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C
50 Ωin series
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D
50 Ω in parallel
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Solution
The correct option is B 0.5 Ω in parallel
i1i2=R2R1=100×10−610×10−3=50x50+x50 (power loss in both the cases will be same)