Question

A galvanometer has a resistance of $400$$\Omega$ . The value of shunt so that its sensitivity is to be reduced by $1/50$ times is

• A. 6.16$\Omega$
• B. 7.16$\Omega$
• C. 8.16$\Omega$
• D. 9.16$\Omega$

Answer 1

Answer: (C)

8.16$\Omega$

Let resistance being connected be $x\Omega$
$R_{eq}$= $\frac{400x}{400+x}=\frac{1}{50}\times 400$
therefore $49x$ = $400$
$x$=$8.16$$\Omega$