Question

A galvanometer having a resistance 98 $\Omega$ is shunted by a wire of resistance 2 $\Omega$ . If the total current is 1 A , find current through the shunt.

Answer 1

Given,

$I=1A$

$G=98\Omega$

$S=2\Omega$

The current flowing through the shunt of galvanometer is,

$I_s=\frac{IG}{G+S}$

$I_s=\frac{1\times 98}{2+98}=\frac{98}{100}$

$I_s=0.98A$