The correct option is
C 1.25ΩGiven: A certain galvanometer has a resistance of
500Ω and gives a full-scale deflection for a current of
200μA. This meter is connected as shown in the figure to make a multi-range current meter.
Connection to the circuit is made at the terminals shown. The currents in the external circuit needed to give full-scale deflections when X is connected to A,B and C, in turn, are shown in the table.
To find R3
Solution:
The given circuit can be re-written as shown in fig(i),
Now applying Kirchhoff's Law, we get
500×200μA=(R1+R2+R3)i1⟹500×200×10−6A=(R1+R2+R3)[1ma−200μA]⟹R1+R2+R3=10×104×10−610−6[1000−200]⟹R1+R2+R3=125....(i)
Now, according to the given criteria, when X is connected to B the circuit becomes as shown in fig(ii), and we get
(500+R1)200μA=(R2+R3)[10mA−200μA]⟹(500+R1)200×10−6=(R2+R3)10−6[10000−200]⟹500+R1=49(R2+R3)....(ii)
Again when X is connected to C the circuit becomes as shown in fig(iii), and we get
(500+R1+R2)200μA=(R3)[100mA−200μA]⟹(500+R1+R2)200×10−6=(R3)10−6[100000−200]⟹500+R1+R2=499(R3)....(iii)
From (i) and (iii),
500+125−R3=499R3⟹500R3=625⟹R3=1.25Ω
is the required value.