The correct option is
A 0.1 in parallel
Given: A galvanometer of 100 resistance gives full scale deflection with 0.01A current
To find the resistance that should be connected convert it into an ammeter of range 10A
Solution:
Galvanometer is a very sensitive instrument therefore it cannot measure heavy currents. In order to convert a Galvanometer into an Ammeter, a very low shunt resistance is connected in parallel to Galvanometer. Value of shunt is so adjusted that most of the current passes through the shunt.
If resistance of galvanometer is Rg and it gives full-scale deflection when current Ig is passed through it. Then,
V=IgRg⟹V=0.01A×100Ω⟹V=1V
Let a shunt of resistance (Rs) is connected in parallel to galvanometer. If total current through the circuit is I.
I=10A=Is+Ig
V=IsRs=(I−Ig)Rs
(I−Ig)Rs=IgRg
(10−0.01)Rs=100×0.01⟹Rs=0.1Ω
is the resistance that should be connected in parallel to convert it into an ammeter of range 10A