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Question

A galvanometer of 50 Ω resistance has 25 divisions. A current of 4×104 A gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 5 V, it should be connected with a resistance of

A
2450 Ω, in parallel
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B
2550 Ω. in series
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C
2450 Ω, in series
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D
2550 Ω, in parallel
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Solution

The correct option is C 2450 Ω, in series
Galvanometer has 25 divisions and current of 4×104 A gives a deflection of 1 division.

the maximum current that can pass through galvanometer isIg=25×4×104=102 A
Range of the voltmeter is, V=25 V and G=50 Ω
So, to convert it into a voltmeter, say, a resistance R must be added in series.
R=VIgG
=2510250=2450 Ω

Hence, (C) is the correct answer.

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