Question

A galvanometer of coil resistance 100 $\Omega$ is connected to a shunt of resistance 10 $\Omega$ . The current through the galvanometer is $i_1$ , the current through the shunt is $i_2$ and the total current into the combination is $i_3$, then the ratio $i_1$ : $i_2$ : $i_3$is

• A. 1 : 10 : 11
• B. 10 : 1 : 11
• C. 11 : 10 : 1
• D. 10 : 11 : 1

Answer 1

The correct option is A 1 : 10 : 11

The two resistances are in parallel. So, equivalent resistance is:

$Req=\frac{100\times 10}{100+10}=\frac{100}{11}$

The voltage across each one is given as $V=I\times R$.

$i_1\left(100\right)=i_2\left(10\right)=i_3\left(\frac{100}{11}\right)$

$i_1:i_2:i_3=1:10:11$