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Question

A galvanometer of coil resistance 99Ω is converted into an ammeter using shunt of 1Ω and is connected as shown in Figure - 1. Ammeter reads 3A. If same galvanometer is converted into voltmeter by connecting a 101Ω resistance in series this voltmeter reads 45 of full scale reading as shown in Figure - 2

A
Internal resistance of cell is r=1.01Ω
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B
Range of ammeter is 5A
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C
Range of voltmeter is 10V
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D
Full scale deflection current of galvanometer is 0.05A
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Solution

The correct option is D Full scale deflection current of galvanometer is 0.05A
By Fig - 1

12=3[2+99×199+1+r]
r=1.01

By Fig - 2

Req=200×2200+2+1.01=2.99Ω
i122.994A

(ii,)×2=200 i1
i1=4101
Given is 45imax=4101imax=51010.05 A
imax is maximum current through galvanometer. Range of voltmeter is Vmax=imax×R=0.05×200=10V


99×0.05=i×1i5A

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