A galvanometer of resistance 100- contain 25 divisions- It gives a deflection of one division on passing a current of 4- 10 -4 A- The resistance in ohm to be added to it- so that it may become a voltmeter of range 2-5V is-

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Conductivity and Resistivity

A galvanomete...

Question

A galvanometer of resistance $100 Ω$ contain $25$ divisions. It gives a deflection of one division on passing a current of $4 \times 10^{- 4} A$ . The resistance in ohm to be added to it, so that it may become a voltmeter of range $2.5 V$ is:

100

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150

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250

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300

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Solution

The correct option is A $150$
The current flowing through the galvanometer is
$I_{g} = (4 \times 10^{- 4}) \times 25 = 10^{- 2} A$
$= \frac{V}{I_{g}} - G = \frac{2.5}{10^{- 2}} - 100 = 150 Ω$

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A galvanometer of resistance 100Ω contain 25 divisions. It gives a deflection of one division on passing a current of 4×10−4A. The resistance in ohm to be added to it, so that it may become a voltmeter of range 2.5V is:

The correct option is A 150The current flowing through the galvanometer isIg=(4×10−4)×25=10−2A=VIg−G=2.510−2−100=150Ω

A galvanometer of resistance $100 Ω$ contain $25$ divisions. It gives a deflection of one division on passing a current of $4 \times 10^{- 4} A$ . The resistance in ohm to be added to it, so that it may become a voltmeter of range $2.5 V$ is:

The correct option is A $150$
The current flowing through the galvanometer is
$I_{g} = (4 \times 10^{- 4}) \times 25 = 10^{- 2} A$
$= \frac{V}{I_{g}} - G = \frac{2.5}{10^{- 2}} - 100 = 150 Ω$