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Question

A galvanometer of resistance 100 Ω gives full scale deflection at 10 mA current. What should be the value of shunt so that it can measure a current of 100 mA?

A
11.11 Ω
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B
1.1 Ω
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C
9.9 Ω
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D
4.4 Ω
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Solution

The correct option is A 11.11 Ω

Galvanometer is a very sensitive instrument therefore it cannot measure heavy currents. In order to convert a Galvanometer into an Ammeter, a very low shunt resistance is connected in parallel to Galvanometer. Value of shunt is so adjusted that most of the current passes through the shunt.

If resistance of galvanometer is Rg and it gives full-scale deflection when current Ig is passed through it. Then,

V=IgRg

V=100mA×100Ω

Let a shunt of resistance (Rs) is connected in parallel to galvanometer. If total current through the circuit is I.

I=10A=Is+Ig

V=IsRs=(IIg)Rs

(IIg)Rs=IgRg

(10103)Rs=100×103

Rs=11.11Ω

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