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Question

A galvanometer of resistance 5Ω is connected in series with a resistance of 0.2 Ω to a battery of negligible internal resistance. The deflection is noted. If the 0.2 Ω resistance is replaced by 2 Ω resistance, the value of shunt resistance to be connected to the galvanometer to maintain the same deflection is

A
1Ω
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B
8.9Ω
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C
0.01Ω
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D
10Ω
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Solution

The correct option is D 8.9Ω
G=5 Ω, R=0.2Ω
I=V5+0.2
Now 0.2 Ω is replaced by 2 Ω
I=V5S5+S+2
5+0.2=5S5+S+2
3.2=5S5+S
16+3.2S=5S
S=161.8=80.9=8.9 Ω

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