A galvanometer of resistance G is shunted by a very small resistance S. The resistance of the resulting ammeter is

GS/(G+S)

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G+S

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G-S

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None of the above

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Solution

The correct option is A GS/(G+S)

We see that the shunt is connected parallel to the galvanometer .

And, equivalent resistance of two resistors connected in parallel is given by

$R = \frac{R_{1} R_{2}}{R_{1} + R_{2}}$

Hence, resistance of ammeter is given by-

$R = \frac{G S}{G + S}$

Answer-(A)

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A galvanometer of resistance G is shunted by a very small resistance S. The resistance of the resulting ammeter is

The correct option is A GS/(G+S)We see that the shunt is connected parallel to the galvanometer .And, equivalent resistance of two resistors connected in parallel is given by R=R1R2R1+R2Hence, resistance of ammeter is given by-R=GSG+SAnswer-(A)

The correct option is A GS/(G+S)

We see that the shunt is connected parallel to the galvanometer .

And, equivalent resistance of two resistors connected in parallel is given by

$R = \frac{R_{1} R_{2}}{R_{1} + R_{2}}$

Hence, resistance of ammeter is given by-

$R = \frac{G S}{G + S}$

Answer-(A)