Question

A game consists of tossing a ₹5 coin twice and noting down its outcomes. Jesika wins if she gets exactly one head. What is the probability that she will lose the game?

• A. $\frac{1}{4}$
• B. $\frac{1}{2}$
• C. $\frac{3}{4}$
• D. $\frac{2}{3}$

Answer 1

The correct option is B $\frac{1}{2}$

Possible outcomes are (HH, HT, TH,TT)
$\therefore$ Total no. of outcomes = 4
Number of favorable Outcomes = 2 (TH, HT)
For an event $\text{E, Probability P(E)}$ = $\frac{\text{Number of outcomes favorable to E}}{\text{Number of all possible outcomes of the experiment}}$

$\therefore$ P(Jesika will win the game)$=\frac{2}{4}=\frac{1}{2}$
For any events events, $\text{P(E)}+P\left(E^{\prime }\right)=1$
$\therefore$ P(Jesika will lose the game)
$=1-\frac{1}{2}=\frac{1}{2}$