A game consists of tossing a one-rupee coin three times, and noting its outcome each time. Find the probability of getting (i) three heads, (ii) at least 2 tails.

Open in App

Solution

Possible outcomes = $(H, H, H), (H, H, T), (H, T, H), (T, H, H), (T, T, H), (T, H, T), (H, T, T), (T, T, T)$

No of possible outcomes = 8

(i) three heads

Favourable outcomes = 1

P(getting three heads) = $\frac{1}{8}$

(ii) at least 2 tails.

Favourable outcomes = $(T, T, H), (T, H, T), (H, T, T), (T, T, T)$ = 4

P(getting at least 2 tails) = $\frac{4}{8} = \frac{1}{2}$

Suggest Corrections

Similar questions

Q. A game consists of tossing a one rupee coin 3 times and noting its outcome each time. Hanif wins if all the tosses give the same result, i.e., three heads or three tails and loses otherwise. Calculate the probability that Hanif will lose the game.

Two dice are rolled once. Find the probability of getting such numbers on two dice, whose product is a perfect square.

A game consists of tossing a coin 3 times and noting its outcomes each time. Hanif wins if he gets three heads or three tails, and loses otherwise. Calculate the probability that Hanif will lose the game.

Three coins are tossed simultaneously 100 times with the following frequencies of different outcomes :

$\begin{matrix} Outcome & No head & One head & Two heads & Three heads Frequency & 14 & 38 & 36 & 12 \end{matrix}$

If the three coins are simultaneously tossed again, compute the compute the probability of :

(i) 2 heads coming up. (ii)3 heads coming up.

(iii) at least one head coming up. (iv) getting more heads than tails.

(v) getting more tails heads.

Q. A coin is tossed three times then find the probability of
(i) getting head on middle coin.
(ii) getting exactly one tail.
(iii) getting no tail.

Join BYJU'S Learning Program

A game consists of tossing a one-rupee coin three times, and noting its outcome each time. Find the probability of getting (i) three heads, (ii) at least 2 tails.

Possible outcomes = (H,H,H),(H,H,T),(H,T,H),(T,H,H),(T,T,H),(T,H,T),(H,T,T),(T,T,T) No of possible outcomes = 8 (i) three heads Favourable outcomes = 1 P(getting three heads) = 18 (ii) at least 2 tails. Favourable outcomes = (T,T,H),(T,H,T),(H,T,T),(T,T,T) = 4 P(getting at least 2 tails) = 48=12