A game was played by a team of 12 players, in which only ${\frac{2}{3}}^{r d}$ of the team actually played the game. The rest were reserve players. How many reserve players did this team have?

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Solution

The correct option is D 4
The team had $12 \times \frac{2}{3}$ = 8 main players. So, (12 - 8) = 4 players were reserve players.

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A game was played by a team of 12 players, in which only 23rd of the team actually played the game. The rest were reserve players. How many reserve players did this team have?

The correct option is D 4The team had 12×23 = 8 main players. So, (12 - 8) = 4 players were reserve players.

A game was played by a team of 12 players, in which only ${\frac{2}{3}}^{r d}$ of the team actually played the game. The rest were reserve players. How many reserve players did this team have?

The correct option is D 4
The team had $12 \times \frac{2}{3}$ = 8 main players. So, (12 - 8) = 4 players were reserve players.