A garden $18 m$ by $15 m$ is surrounded by a path of uniform width $2.25.$ Find the area of the path.

Open in App

Solution

$\begin{matrix} A r e a o f g a r d e n = l e n g t h \times b r e a d t h = 18 \times 15 = 270 m^{2} N o w, L e n g t h o f p a t h = 18 + 2.25 + 2.25 = 22.5 m B r e a d t h o f p a t h = 15 + 2.25 + 2.25 = 19.5 m A r e a o f g a r d e n w i t h p a t h = 22.5 \times 19.5 = 438.15 m^{2} T h e n A r e a o f p a t h = A r e a o f g a r d e n w i t h p a t h - a r e a o f g a r d e n = 438.75 - 270 = 168.75 m^{2} \end{matrix}$
Hence, the area of path is $168.75 m^{2}$ .

Suggest Corrections

Similar questions

4 m

24 m

18 m

A path of uniform width 1.5 m runs around the outside of a rectangular field 18 m by 15 m. The area of the path is _____ $m^{2}$ .

m^{2}

55

35

m^{2}

m^{2}

Join BYJU'S Learning Program