A garden is 30 yd long. A gardener waters it at a constant speed of $6^{- 1}$ ft/ minute. In how many minutes will the gardener take to water the entire garden?

500

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540

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600

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570

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Solution

The correct option is B 540
Length of the garden = 30 yd
= 30 $\times$ 3 ft $(∵ 1 yd = 3 ft)$
The speed is $6^{- 1}$ ft/s.
So, the time for watering = $\frac{90}{6^{- 1}} = \frac{90}{\frac{1}{6}} [∵ 6^{- 1} = \frac{1}{6}] = 90 \times 6 = 540 m i n u t e s$

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A garden is 30 yd long. A gardener waters it at a constant speed of 6−1 ft/ minute. In how many minutes will the gardener take to water the entire garden?

The correct option is B 540Length of the garden = 30 yd = 30 × 3 ft (∵1 yd = 3 ft) The speed is 6−1ft/s. So, the time for watering = 906−1=9016 [∵6−1=16]=90×6=540 minutes

A garden is 30 yd long. A gardener waters it at a constant speed of $6^{- 1}$ ft/ minute. In how many minutes will the gardener take to water the entire garden?

The correct option is B 540
Length of the garden = 30 yd
= 30 $\times$ 3 ft $(∵ 1 yd = 3 ft)$
The speed is $6^{- 1}$ ft/s.
So, the time for watering = $\frac{90}{6^{- 1}} = \frac{90}{\frac{1}{6}} [∵ 6^{- 1} = \frac{1}{6}] = 90 \times 6 = 540 m i n u t e s$