A gardener uses pipes to water his garden from the tank. For his entire garden he uses 6 pipes to water and it takes him 1 hour 20 minutes to completely empty the tank. Now if he uses only 5 pipes to water his garden, how long it will take him to empty the tank?

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Solution

Let the time required be x.
$\begin{matrix} N o . o f p i p e s & 6 & 5 T i m e t a k e n (m i n) & 80 & X \end{matrix}$
$∴$ It is inverse variation.

$\frac{6}{5}$ = $\frac{x}{80}$
x = $\frac{6 \times 80}{5}$ = 96 mins
x =1 hour 36 mins (2 mark)

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A gardener uses pipes to water his garden from the tank. For his entire garden he uses 6 pipes to water and it takes him 1 hour 20 minutes to completely empty the tank. Now if he uses only 5 pipes to water his garden, how long it will take him to empty the tank?

Let the time required be x. No. of pipes65Time taken (min)80X ∴ It is inverse variation. 65 = x80 x =6×805 = 96 mins x =1 hour 36 mins (2 mark)

Let the time required be x.
$\begin{matrix} N o . o f p i p e s & 6 & 5 T i m e t a k e n (m i n) & 80 & X \end{matrix}$
$∴$ It is inverse variation.

$\frac{6}{5}$ = $\frac{x}{80}$
x = $\frac{6 \times 80}{5}$ = 96 mins
x =1 hour 36 mins (2 mark)