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Standard XII

Chemistry

Introduction

A gas absorbs...

Question

A gas absorbs 100 J of heat and simultaneously is compressed by a constant external pressure of 1.50 atm from 8 L to 2 L. $Δ U$ will be:

109 J

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812 J

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1011 J

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911 J

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Solution

The correct option is C 1011 J
Given that, the gas absorbs 100 J of heat
So, $q = 100 J$
We know,
$W = - P Δ V$
$= - 1.50 (2 - 8) = 9 a t m$
$= 9 \times 101.3 J$
From the first law of thermodynamics,
$Δ U = q + w$
$= 100 + 911.7$
$= 1011 J$

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A gas absorbs 100 J of heat and simultaneously is compressed by a constant external pressure of 1.50 atm from 8 L to 2 L. ΔU will be:

The correct option is C 1011 JGiven that, the gas absorbs 100 J of heat So, q=100 J We know, W=−PΔV =−1.50(2−8)=9 atm =9×101.3J From the first law of thermodynamics, ΔU=q+w =100+911.7 =1011J

A gas absorbs 100 J of heat and simultaneously is compressed by a constant external pressure of 1.50 atm from 8 L to 2 L. $Δ U$ will be:

The correct option is C 1011 J
Given that, the gas absorbs 100 J of heat
So, $q = 100 J$
We know,
$W = - P Δ V$
$= - 1.50 (2 - 8) = 9 a t m$
$= 9 \times 101.3 J$
From the first law of thermodynamics,
$Δ U = q + w$
$= 100 + 911.7$
$= 1011 J$