A gas absorbs 100 J of heat and simultaneously is compressed by a constant external pressure of 1.50 atm from 8 L to 2 L. ΔU will be:
A
109 J
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B
812 J
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C
1011 J
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D
911 J
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Solution
The correct option is C 1011 J Given that, the gas absorbs 100 J of heat So, q=100J We know, W=−PΔV =−1.50(2−8)=9atm =9×101.3J From the first law of thermodynamics, ΔU=q+w =100+911.7 =1011J