A gas absorbs 200 J of heat and expands against the external pressure of 1.5 atm from a volume of 0.5 litres to 1.0 litre.
Calculate the change in internal energy.

124 J

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224 J

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114 J

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154 J

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Solution

The correct option is A $124 J$
Given: Heat supplied $Q = 200 J$
$P_{e x t e r n a l} = 1.5 a t m, V_{1} = 0.5 L; V_{2} = 1.0 L$

Using the relation, $△ U = Q + W$

$W = - P_{e x t} (V_{2} - V_{1}) = - 1.5 a t m (1.0 - 0.5) L$ ; $[1 L . a t m = 101.33 J o u l e]$

$W = - 1.5 \times 0.5 L . a t m = - 0.75 L . a t m$

$W = - 0.75 \times 101.33 J o u l e$

$W = - 75.99 J o u l e$

$\Rightarrow △ U = 200 J - 75.99 J = 124.0 J$

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A gas absorbs 200 J of heat and expands against the external pressure of 1.5 atm from a volume of 0.5 litres to 1.0 litre. Calculate the change in internal energy.

The correct option is A 124 JGiven: Heat supplied Q=200 JPexternal=1.5 atm, V1=0.5 L; V2=1.0 LUsing the relation, △U=Q+WW=−Pext(V2−V1)=−1.5 atm(1.0−0.5) L; [1 L.atm=101.33 Joule]W=−1.5×0.5 L.atm=−0.75 L.atmW=−0.75×101.33 JouleW=−75.99 Joule⇒△U=200 J−75.99 J=124.0 J

A gas absorbs 200 J of heat and expands against the external pressure of 1.5 atm from a volume of 0.5 litres to 1.0 litre.
Calculate the change in internal energy.