A gas absorbs 400 J of heat and expands by 2- 10-3m3 against a constant pressure of 1- 105Nm-2- The change in internal energy is 1 L atm-100 J

A gas absorbs 120 J of heat and expands against the external pressure of 1.10atm from a volume of 0.5 litre to 2.0 litre .What is the change in internal energy ? (1Latm =101.3J)

Q. One mole of a gas absorbs

200 J

of heat at constant volume. Its temperature rises from

298 K

308 K

. The change in internal energy is-

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A gas absorbs 400 J of heat and expands by 2×10−3m3 against a constant pressure of 1×105Nm−2. The change in internal energy is (1 L atm=100 J)

The correct option is D 200JFrom the First law of thermodynamics, Change in internal energy,δU=Q+W⇒δU=Q−PδV⇒δU=400−(1×105)(2×10−3)⇒δU=400−200JTherefore, δU=200JHence,option B is correct.

A gas absorbs $400 J$ of heat and expands by $2 \times 10^{- 3} m^{3}$ against a constant pressure of $1 \times 10^{5} N m^{- 2}$ . The change in internal energy is $(1 L a t m = 100 J$ )

The correct option is D $200 J$
From the First law of thermodynamics,
Change in internal energy, $δ U = Q + W$
$\Rightarrow δ U = Q - P δ V$
$\Rightarrow δ U = 400 - (1 \times 10^{5}) (2 \times 10^{- 3})$
$\Rightarrow δ U = 400 - 200 J$
Therefore, $δ U = 200 J$
Hence,option B is correct.