Question

A gas at $0^{\circ }$ is heated. Both its pressure and volume increases twice the initial value. Find the final temperature of the gas.

• A. ${819}^{\circ }C$
• B. ${719}^{\circ }C$
• C. ${891}^{\circ }C$
• D. ${791}^{\circ }C$

Answer 1

The correct option is A

${819}^{\circ }C$

From the combined laws of Boyle's and Charles' law, $\frac{PV}{T}=\frac{P_1{V}_1}{T_1}$

Now, $\frac{PV}{273}=\frac{2P\times 2V}{T_1}$

$\Rightarrow T_1=273\times 4$

$\Rightarrow T_1=1092$

Therefore, Final temperature of the gas = ($1092-273{)}^{\circ }C={819}^{\circ }C$