Question

A gas at $0^{o}C$ and 1 atm pressure occuples 2.5 litre. What change in temperature would be necessary pressure is to be adjusted to 1.5 atm and the gas has been transferred to a 2.0 litre container?

Answer 1

$P_1=1atm{P}_2=1.5atm$

$V_1=2.5L{P}_2=2.0L$

$T_1=0°C=273K{T}_2=?$

According to Boyle's law,

$\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$

$\therefore \frac{1\times 25}{273K}=\frac{1.5\times 2}{T_2}$

$\therefore$ $T_2=\frac{1.5\times 2\times 273}{1\times 2.5}=327.78K=54.63°C$