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Byju's Answer
Standard XII
Physics
KE
A gas at 27de...
Question
A gas at 27degree celcius has a volume v and pressure p. On heating its pressure is doubled and volume becomes 3times. The resulting temperature of the gas will be
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Solution
Dear Student,
T
1
= 27 +273 =300
K
V
1
=
V
V
2
=3
V
T
2
=?
use
P
1
V
1
/
T
1
=
P
2
V
2
/
T
2
G
i
v
e
n
P
1
=
2
P
2
S
o
V
1
/
T
1
=
2
V
2
/
T
2
V
/300 = 3
×
2
×
V
/
T
2
T
2
=
1800
K
=
1527
C
Regards
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