Question

A gas at a pressure of 2.0 $atm$ is heated at room temperature, $0^{0}C$ to ${273}^{0}C$ and the volume compressed to 1/4th of its original volume. Find the final pressure.

• A. 12 $atm$
• B. 8 $atm$
• C. 16 $atm$
• D. 20 $atm$

Answer 1

The correct option is C 16 $atm$

As per the ideal gas law; $\frac{P_1\times V_1}{T_1}=\frac{P_2\times V_2}{T_2}$

Therefore $\frac{2\times V_1}{273}=\frac{P_2\times \left(V_1/4\right)}{546}$

Thus $P_2=\frac{2\times 4\times 546}{273}$ = $16atm$