Question

A gas at a pressure of $5atm$ is heated from $0^o$ to ${546}^{o}C$ and simultaneous compressed to $\frac{1}{3}rd$ of it original volume. Hence final pressure is?

• A. $10atm$
• B. $45atm$
• C. $30‘atm$
• D. $5atm$

Answer 1

The correct option is B $45atm$

Here $\frac{PV}{T}=constant$

Given $V_2=\frac{V_1}{3},$ $P_1=5atm,T_1=273K,T_2=819K$

$\therefore \frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$

$\therefore P_2=P_1\left(\frac{V_1}{V_2}\right)\left(\frac{T_2}{T_1}\right)=5\times 3\times \frac{819}{273}=45atm$