Question

A gas at pressure $p$ has volume $V$. It is adiabatically compressed to volume $V/32$. If $(32{)}^{1.4}=128$, what is the current pressure of the gas?

• A. $128p$
• B. $63p$
• C. $32p$
• D. $16p$

Answer 1

The correct option is A $128p$

$P{V}^{\gamma }=Constant{P}_1{V}_1^{\gamma }=P_2{V}_2^{\gamma }{P}_2=P_1\times (\frac{V_1}{V_2}{)}^{\gamma }=P\times (\frac{V}{\frac{V}{32}}{)}^{1.4}[\gamma =1.4]=P\times ({32)}^{1.4}{P}_2=128P$