You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Wave Equation

A gas bubble ...

Question

A gas bubble of $2 c m$ diameter rises through a liquid of density $1.75 g$ ${c m}^{- 3}$ with a fixed speed of $0.35 {c m s}^{- 1}$ . Neglect the density of the gas. The co-efficient of viscosity of the liquid is

870

poise

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1120

poise

No worries! We‘ve got your back. Try BYJU‘S free classes today!

982

poise

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1089

poise

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $1089$ poise
Since the bubble rises with constant speed, the net force acting on the bubble must be zero.
Hence $V ρ g = 6 π η r v$ (Since the density of gas is negligible, its weight has no contribution)
$⟹ (\frac{4}{3} π 1^{3}) (1.75) (981) = 6 π η (1) (0.35)$
$⟹ η = 1089 p o i s e$

Suggest Corrections

Similar questions

An air bubble of diameter 2 mm rises steadily through a solution of density 1750 kg m^-3 at the rate of 0.35 cm s^-1. Calculate the coefficient of viscosity of the solution. The density of air is negligible.

Q. A gas bubble of 2 cm diameter rises through a liquid of density 1.75 gm

c m^{- 3}

with a fixed speed of 0.35 cm

s^{- 1}

. Neglect the density of the gas. The coefficient of viscosity of the liquid is:

Q. An air bubble of diameter

4 mm

rises steadily through a solution of density

1800 {kg/m}^{3}

at the rate of

0.05 m/s

. Neglecting density of air, the co-efficient of viscosity of the solution is
[Take

g = 10 {m/s}^{2}

]

Q. An air bubble of radius

r = 3 m m

moves up in a viscous liquid with a constant velocity

v = 0.7 c m / s

and the density of the liquid is

1.75 g / c c

. If viscosity of liquid (in poise) is given by

10 x

then

x

will be (Neglect the density of air in comparision to that of the liquid.)

The terminal velocity of a steel ball of 4 mm in diameter falling through a glycerin of viscosity 3.3 poise, given relative density of steel is 8, relative density of glycerin is 1.3 is

Join BYJU'S Learning Program

A gas bubble of 2cm diameter rises through a liquid of density 1.75g cm−3 with a fixed speed of 0.35cms−1. Neglect the density of the gas. The co-efficient of viscosity of the liquid is

The correct option is D 1089 poiseSince the bubble rises with constant speed, the net force acting on the bubble must be zero.Hence Vρg=6πηrv(Since the density of gas is negligible, its weight has no contribution)⟹(43π13)(1.75)(981)=6πη(1)(0.35)⟹η=1089poise

A gas bubble of $2 c m$ diameter rises through a liquid of density $1.75 g$ ${c m}^{- 3}$ with a fixed speed of $0.35 {c m s}^{- 1}$ . Neglect the density of the gas. The co-efficient of viscosity of the liquid is