Question

A gas cylinder containing cooking gas can withstand a pressure of $14.9$ atm. The pressure guage of the cylinder indicates $12$ atm at ${27}^{o}C$. Due to sudden fire in the building, its temperature stats rising. At what temperature cylinder will explode?

Answer 1

$P_1=12bar,T_1=27+273=300K$
$P_2=14.9bar,T_2=?$

Applying pressure temperature law,
$\frac{P_1}{P_2}=\frac{T_1}{T_2}$

or $T_2=\frac{T_1\times P_2}{P_1}$
Substituting the values in the above equation,
$T_2=\frac{300\times 14.9}{12}=372.5K$

Temperature in ${}^{0}C$$=372.5-273=$${99.5}^{\circ }C$

Hence the cylinder will explode at a temperature ${99.5}^{\circ }C$