A gas cylinder contains 24 - 1024 molecules of nitrogen gas- If Avogadro-s number is 6 - 1023 and the relative atomic mass of nitrogen is 14 - calculate-

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A gas cylinde...

Question

A gas cylinder contains 24 x 10²⁴ molecules of nitrogen gas. If Avogadro’s number is 6 x 10²³ and the relative atomic mass of nitrogen is 14, calculate:

1.75 kg, 850 kg

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1.12 kg, 600 kg

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2.03 kg, 740 kg

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2.03 kg, 720 kg

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1.12 kg, 896 kg

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3.00 kg, 650 kg

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Solution

The correct option is E
1.12 kg, 896 kg

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Similar questions

(a) A gas cylinder contains 24 × 10²⁴ molecules of nitrogen gas. If Avogadro's number is 6 × 10²³ and the relative atomic mass of nitrogen is 14, calculate:
(i) Mass of nitrogen gas in the cylinder.
(ii) Volume of nitrogen at STP in dm³.

(b) Commercial sodium hydroxide weighing 30 g has some sodium chloride in it. The mixture on dissolving in water and subsequent treatment with excess silver nitrate solution formed a precipitate weighing 14.3 g.What is the percentage of sodium chloride in the commercial sample of sodium hydroxide? The equation for the reaction is
NaCl + AgNO₃ → AgCl + NaNO₃.
[Relative molecular mass of NaCl = 58; AgCl = 143]

(c) A certain gas 'X' occupies a volume of 100 cm³ at S.T.P. and weighs 0.5 g. Find its relative molecular mass.

Q. A gas cylinder contains

12 \times 10^{24}

molecules of oxygen gas.
If Avogadro's number is

6 \times 10^{23}

; Calculate:
(i) the mass of oxygen present in the cylinder.
(ii) the volume of oxygen at S.T.P. present in the cylinder.

[O = 16]

(a) A gas cylinder of capacity of $20 d m^{3}$ is filled with gas X the mass of which is 10 g. When the same cylinder is filled with hydrogen gas at the same temperature and pressure the mass fo the hydrogen is 2 g, hence the relative molecular mass of the gas is :
(i) 5 (ii) 10 (iii) 15 (iv) 20
(b) (i) Calcium carbide is used for the artificial ripening of fruits. Actually the fruit ripens beause fo the heat evolved while calcium carbide reacts with and acetylene gas is formed. If $200 c m^{3}$ of acetylene is formed from a certain mass of calcium carbidem, find the volume of oxygen required and carbon dioxide formed during the complete combustion. The combustion reaction can be represented as below.
$2 C_{2} H_{2} (g) + 5 O_{2} (g) \to 4 C O_{2} (g) + 2 H_{2} O (g)$
(ii) A gaseous compound of nitrogen and hydrogen contains 12.5% hydrogenj by mass. Find the molecular formula of the ocmpound if its relative molecular mass is 37. $[N = 14, H = 1] .$
(c) (i) A gas cylinder contains $24 \times 10^{24}$ moleules of nitrogen gas. If avogadro's number is $6 \times 10^{23}$ and the relative atomic mass of nitrogen is 14, calculate:
(1) Mass of nitrogen gas in th ecylinder
(2) Volume of nitrogen at STP in $d m^{3}$
(ii) Commercial sodium hydroxide wieghing 30 g has some sodium chloride in it. The mixture on dissolving in water and subsequent treatment with excesss silver nitrate solution formed a precipitate weighing 14.3 g. What is the percentage fo sodium chloride in the commercial sample of sodium hydroxide? The equation for the reaction is
$N a C l + A g N O_{3} \to A g C l + N a N O_{3}$
[Relative molecular mass of $N a C l = 58; A g C l = 143$ ]
(iii) A certain Gas 'X' occupies a volume of $100 c m^{3}$
at S.T.P. and weighs 0.5 g. Find its relative moleular mass.

Q. Since Avogadro number is

6.023 \times 10^{23}

and atomic mass of nitrogen is

14

amu, one mole of

N_{2}

gas will have:

Calculate the number of molecules in 12.8 g of sulphur dioxide gas. Take Avogadro's number as 6 × 10²³.
[S = 32, O = 16]

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A gas cylinder contains 24 x 1024 molecules of nitrogen gas. If Avogadro’s number is 6 x 1023 and the relative atomic mass of nitrogen is 14, calculate:

The correct option is E 1.12 kg, 896 kg

A gas cylinder contains 24 x 10²⁴ molecules of nitrogen gas. If Avogadro’s number is 6 x 10²³ and the relative atomic mass of nitrogen is 14, calculate:

The correct option is E
1.12 kg, 896 kg