A gas cylinder contains $5$ moles of oxygen gas.The weight of the gas in the cylinder is:

80

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120

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160

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40

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Solution

The correct option is D $160$ g
One mole of oxygen i.e. $O_{2}$ = $16 \times 2 = 32$
five moles of oxygen = $32 \times 5 = 160$ g

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A gas cylinder contains 5 moles of oxygen gas.The weight of the gas in the cylinder is:

The correct option is D 160 gOne mole of oxygen i.e. O2 =16×2=32five moles of oxygen = 32×5=160 g

A gas cylinder contains $5$ moles of oxygen gas.The weight of the gas in the cylinder is:

The correct option is D $160$ g
One mole of oxygen i.e. $O_{2}$ = $16 \times 2 = 32$
five moles of oxygen = $32 \times 5 = 160$ g