A gas decolourised by $K M n O_{4}$ solution but gives no precipitate with ammoniacal cuprous chloride is:

ethane

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methane

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ethene

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acetylene

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Solution

The correct option is A ethene
A gas decolourised by $K M n O_{4}$ solution but gives no precipitate with ammoniacal cuprous chloride is ethene $C H_{2} = C H_{2}$ . Since it contains carbon-carbon double bond, it reacts with $K M n O_{4}$ to form vicinal diol. Hence, $K M n O_{4}$ is decolourised.
$C H_{2} = C H_{2} + H_{2} O + (O) alkaline K M n O_{4} - -------- \to H O - C H_{2} - C H_{2} - O H$
Note: Acetylene gives a precipitate with ammoniacal cuprous chloride.

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