A gas expand adiabatically at constant pressure such that T - V -3-4- The value of Y C p - C V of the gas will be-A- 1-75B- 1-33C- 1-6D- 1-5

The correct option is A 1.75Given: nbsp; T∝ V^ 3/4 nbsp; T = kV^ 3/4 nbsp; nbsp;or k = T V^3/4....(1) We also know, For adiabatic process k = T V^γ ...

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Standard XII

Chemistry

Thermodynamic Processes

A gas expand ...

Question

A gas expand adiabatically at constant pressure such that
$T \propto V^{\frac{- 3}{4}}$ . The value of $γ (\frac{C_{p}}{C_{v}}$ ) of the gas will be:

1.5

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1.75

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1.33

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1.6

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Solution

The correct option is B 1.75
Given: $T \propto V^{\frac{- 3}{4}}$
$T = k V^{\frac{- 3}{4}}$ or
$k = T V^{\frac{3}{4}}$ ....(1)

We also know,
For adiabatic process
$k = T V^{γ - 1}$ ....(2)
where $k =$ constant

equating both the equations we get,
$T V^{\frac{3}{4}} = T V^{γ - 1}$
$γ - 1 = \frac{3}{4}$
$γ = \frac{7}{4} = 1.75$

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A gas expand adiabatically at constant pressure such that T∝V−34. The value of γ (CpCv) of the gas will be:

The correct option is B 1.75Given: T∝V−34 T =kV−34 or k=TV34....(1) We also know, For adiabatic process k=TVγ−1....(2) where k= constant equating both the equations we get, TV34=TVγ−1 γ−1=34 γ=74=1.75

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