wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A gas expands adiabatically at constant pressure, such that its temperature T1V. The value of Cp/CV of the gas is:

A
1.3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1.67
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1.5
Key Idea Sudden expansion is adiabatic operation. An adiabatic relation between p and V is
pVγ=k, a constant.
A change in pressure and volume of a gas in which temperature also changes is called an adiabatic change. In such a change, no heat is allowed to enter into or escape from the gas (ie, there is no exchange of heat between the gas and its surroundings).
For adiabatic expansion, we have the formula
pVγ= constant ...(i)
Gas equation is,
pV=RT
p=RTV ...(ii)
From Eqs. (i) and (ii), we obtain
(RTV)Vγ= constant
TVγ1=constant ...(iii)
But T1V (given)
as TV1/2= constant ...(iv)
Thus, using Eqs. (iii) and (iv) together, we get
γ1=12
or γ=32=1.5
CpCv=1.5

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon