A gas expands adiabatically from 1.0 L to 12.0 L against a constant pressure of 0.75 atm. The â–³U of the gas is
A
- 835.9 J
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B
853.9 J
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C
859.9 J
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D
- 839.5 J
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Solution
The correct option is A - 835.9 J First law of thermodynamics △U=Q+W Q=0 (adibatic expansion) so,△U=W △U=W=−pext△V=−(0.75atm)(12.0L−1.0L) =8.25Latm ≡−(8.25Latm)(8.314J0.082Latm)=−835.9J