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Question
A gas expands by 0.5 litre against a constant pressure of one atmosphere. Calculate the work done in joule and calorie.
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Solution
Work=−Pext×volumechange
=−1×0.5=−0.5 litre-atm
=−0.5×101.328J=−50.664J
0.5litre−atm=−0.5×24.20=−12.10cal
=−1×0.5=−0.5 litre-atm
=−0.5×101.328J=−50.664J
0.5litre−atm=−0.5×24.20=−12.10cal
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